anonymous
  • anonymous
Subtract 5/(x^2-xy) - 5/(y^2-xy). Could somebody explain to me how to do this?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
You must have the same denominators so :\[= [5(y-x) - 5(x-y)]/x(x-y)(y-x)\]\[= (5y-5x-5x+5y)/x(x-y)(y-x) \]\[= (10y-10x)/x(x-y)(y-x)\]\[= 10(y-x)/x(x-y)(y-x)\]\[= 10/x(x-y)\] ^_^
anonymous
  • anonymous
what I really need is how to find the LCD? I'm kind of confused
anonymous
  • anonymous
first factor, then you have to multiply both sides to get the same denominator

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
isn't the denominator xy(x-y)(x-y)?
anonymous
  • anonymous
or am i wrong?
anonymous
  • anonymous
if you notice , when you factor the denominator on the first side you'll get : x(x-y) and when you factor the denominator of the other side you get : x(y-x) we have x in common, but one has (x-y) and the other has (y-x) so we multiply the first one with (y-x) and the second one with (x-y) so both can have : x(x-y)(y-x) the same denominator ^_^ clearer now? :)
anonymous
  • anonymous
no laka, youre right...
anonymous
  • anonymous
no laka, it's not ^_^ you'll get x^3
anonymous
  • anonymous
starica, the second denominator, factored, gives you y(y-x) not x(y-x)
anonymous
  • anonymous
yeah i realised
anonymous
  • anonymous
you sure?
anonymous
  • anonymous
oh right! ^^" sorry for the mess again
anonymous
  • anonymous
xy(y-x)(x-y)?
anonymous
  • anonymous
so you'll have to multiply x and y with the others too
anonymous
  • anonymous
yes laka, you are right dear, thank you ^_^
anonymous
  • anonymous
answer should be something like 5(xx-yy)/xy(x-y)(y-x) or 5(xx-yy)/-xy(x-y)^2 aka -5(xx-yy)/(xy(x-y)^2
anonymous
  • anonymous
I'll have to redo it again ._.
anonymous
  • anonymous
im curious starica, how are you on here like all day? O.o
anonymous
  • anonymous
lol I wasn't here all day ^_^ I come in mornings and nights only
anonymous
  • anonymous
outcast girl the answer is :\[= 5y(y-x) - 5x(x-y)/xy(y-x)(x-y)\]\[= 5y^2 -5xy -5x^2 +5xy/xy(x-y)(y-x)\]\[= 5(y^2-x^2)/xy(x-y)(y-x)\]\[= 5(y-x)(y+x)/xy(x-y)(y-x)\]\[= 5(y+x)/xy(x-y)\] for the mess up, I'm sure this time ^_^
anonymous
  • anonymous
sorry for the mess*
anonymous
  • anonymous
that's correct :)
anonymous
  • anonymous
how do you get the pretty notation?
anonymous
  • anonymous
yay , lol ^_^
anonymous
  • anonymous
click on equation and write it down ^_^
anonymous
  • anonymous
ohhhhhhhh, makes sense
anonymous
  • anonymous
something called equation on youer reply box :)
anonymous
  • anonymous
thanks! I think I got it now :)
anonymous
  • anonymous
your*
anonymous
  • anonymous
most welcome ^_^!
radar
  • radar
Just a suggestion mind you. the second term that is factored as:\[-5/y(y-x)\] can be simplified by changing it to the following:\[+(5/(x-y)\] This can be done by multiply by -1 twice, once changing the - to a plux making it and addition and then again changeing the y(y-x) to y(x+y) I think thats legal. Don't know if that will help or not
radar
  • radar
Is that legal?
radar
  • radar
Oooops Change the last line on the post 2nd above to read y(x-y)
anonymous
  • anonymous
hmm, it's true, it can be, but I'm not sure though, wouldn't that change the function completely?
radar
  • radar
I wondering too, but multiplying by -1 one twice is the same as multiplying by a +1 and theoretically shouldn't change it.
anonymous
  • anonymous
you have just answered the question in a much simpler way! thank you ^_^!
anonymous
  • anonymous
yes thank you!
anonymous
  • anonymous
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.