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anonymous
 5 years ago
(xy)/(x+y)(xy) is it legal to remove (xy) leaving me with 1/(x+y) ?
anonymous
 5 years ago
(xy)/(x+y)(xy) is it legal to remove (xy) leaving me with 1/(x+y) ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can cancel (xy) from top and bottom ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As long as \[x \neq y\].

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can just simply simplify without looking at that condition ^_^

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(xy)  (x+y)(xy) What looks like "canceling" like terms top to bottom is actually misleading. What you are doing is seperating the fraction into parts; and anything that is equal to (1) stays there, but is implied. 1 (xy) 1   =  times (1) (x+y) (xy) (x+y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You must have the condition that x does not equal y. Because along the line x=y you will have a discontinuity in your graph. Specifically a hole I think. The function is not defined there.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0If we are talking about the graph of the function, then you are correct. If we can "cross out" like terms it will create a hole in the graph, a jump discontinuity.
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