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anonymous

  • 5 years ago

An airplane flying into a headwind travels 224 miles in 2 hours and 40 minutes. On the return flight, the distance is traveled in 2 hours. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

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  1. anonymous
    • 5 years ago
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    assume the speed of the air is v1 and the speed of the airplane is v2.. we have the following two equations: \[v2-v1=224miles/160\min\] \[v2+v1=224miles/120\min\] solve the two equations for v1 and v2

  2. anonymous
    • 5 years ago
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    actually the speed of airspeed and the wind can't be assumed as constant value...

  3. anonymous
    • 5 years ago
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    the speed of the airplane v2=1.63 miles/min the speed of the air v1=0.23miles/min

  4. anonymous
    • 5 years ago
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    Why can you not assume the that the airspeed and windspeed remain constant?

  5. anonymous
    • 5 years ago
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    it might be right if the fraction of the air being neglected

  6. amistre64
    • 5 years ago
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    The problem says to assume constant speeds; regardless of whether it conforms to real events :)

  7. anonymous
    • 5 years ago
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    so then i think anwar is right...

  8. anonymous
    • 5 years ago
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    so would you say...? plane speed = 98 mph; wind speed = 14 mph?

  9. anonymous
    • 5 years ago
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    yes, though i may add in a few decimal places for accuracy

  10. anonymous
    • 5 years ago
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    yes.. 1.63miles/min*60min/hour=97.8mph 0.23miles/min*60min/hour=13.8mph

  11. anonymous
    • 5 years ago
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    Ok well thanks for helping it makes a lot more sense now! Thanks everyone!

  12. anonymous
    • 5 years ago
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    you're welcome

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