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anonymous
 5 years ago
wx^2+wl/2wx simplified to wlx/2wx^2/2
can someone show me how they got there thanks!
anonymous
 5 years ago
wx^2+wl/2wx simplified to wlx/2wx^2/2 can someone show me how they got there thanks!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it : \[wx^2  (wl/2)\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it : wx^2 + (wl/2wx) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure of your answer? because I got in the end :\[wx^2 + wl\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you show me how you got wx^2 + wl

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0steps, first same denominator:\[= (wx^2(2wx) + wl) /2wx\]\[= (2wx^2 w^2x^3 + wl)/2wx\] then multiply by 2+wx up and down:\[= (2wx^2w^2x^3+wl)(2+wx)/(2wx)(2+wx)\]\[= (4wx^2w^3x^4 + 2wl + w^2xl)/(2wx)(2+wx)\] then factor by grouping :\[= [wx^2(4w^2x^2) + wl(2 + wx)]/(2wx)(2+wx)\]\[= [wx^2(2wx)(2+wx) + wl(2+wx)]/(2wx)(2+wx)\]\[= [(2+wx)(2wx)(wx^2+wl)]/(2wx)(2+wx)\] simplify (cancel the commons) : \[= wx^2 + wl\] ^_^ correct me if I'm wrong please .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you use a program to type the formulas?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, click on equation on your reply box and type the formula there ^_^
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