anonymous
  • anonymous
wx^2+wl/2-wx simplified to wlx/2-wx^2/2 can someone show me how they got there thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
is it : \[wx^2 - (wl/2)\]?
anonymous
  • anonymous
wx^2 - wl/2 - wx *
anonymous
  • anonymous
is this the question?

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anonymous
  • anonymous
+wl/2
anonymous
  • anonymous
lol okay ^^"
anonymous
  • anonymous
is it : wx^2 + (wl/2-wx) ?
anonymous
  • anonymous
yes
anonymous
  • anonymous
are you sure of your answer? because I got in the end :\[wx^2 + wl\]
anonymous
  • anonymous
could you show me how you got wx^2 + wl
anonymous
  • anonymous
steps, first same denominator:\[= (wx^2(2-wx) + wl) /2-wx\]\[= (2wx^2 -w^2x^3 + wl)/2-wx\] then multiply by 2+wx up and down:\[= (2wx^2-w^2x^3+wl)(2+wx)/(2-wx)(2+wx)\]\[= (4wx^2-w^3x^4 + 2wl + w^2xl)/(2-wx)(2+wx)\] then factor by grouping :\[= [wx^2(4-w^2x^2) + wl(2 + wx)]/(2-wx)(2+wx)\]\[= [wx^2(2-wx)(2+wx) + wl(2+wx)]/(2-wx)(2+wx)\]\[= [(2+wx)(2-wx)(wx^2+wl)]/(2-wx)(2+wx)\] simplify (cancel the commons) : \[= wx^2 + wl\] ^_^ correct me if I'm wrong please .
anonymous
  • anonymous
thank you!!!
anonymous
  • anonymous
a pleasure :)
anonymous
  • anonymous
do you use a program to type the formulas?
anonymous
  • anonymous
no, click on equation on your reply box and type the formula there ^_^
anonymous
  • anonymous
"equation" *

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