At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

+2.6 ?

and yes 2.6 is the common difference (d)

1.6 + 2.6(n) ?? think I am wrong...

my answer choices are:
A. 2090
B.3395
C.3265
D.3266
E.3264

would it not be 1.6+2.6(n-1) ?? Remembering that you start at n=1

math: thats what I thought, but doubted myself....

Well thats what I was doing but as you can see none of my answer choices match that answer

that's because you are looking for the sum of the terms up o the 50th term

ohhhh wow silly me so I have to go back and add them all up.... sorry about that

the idea of the question i assume is for you to find the formula which does the sumation for you

can you do that with an integral of the equation?

i think to find n, you could use 50=n/2 (1.6+(n-1)2.6)

\[s \left[ n \right]=n\2(a \left[ 1 \right]+a \left[ n \right])\]

maybe?

no I don't think that is right either.....

no its not, keep trying though

Just kidding I figured it out the answer is c

1.6+49(2.6)=129
50/2(1.6+129)=3265

oh i see what you meant now by your notation! My mistake, well done :)

if i remember correctly there is a formula for the sum of an infinite series, first take 2 out as it is a constant and then apply the formula, (try wikipedia for it because i cannot be sure of my memory). As -1

Ok thanks