Find the indicated nth partial sum of the arithmetic sequence. 1.6, 4.2, 6.8, 9.4, ..., n = 50

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Find the indicated nth partial sum of the arithmetic sequence. 1.6, 4.2, 6.8, 9.4, ..., n = 50

Mathematics
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+2.6 ?
The nth term = dn + c. I think I use this to solve but when I do none of my answers match up with my choices
and yes 2.6 is the common difference (d)

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1.6 + 2.6(n) ?? think I am wrong...
my answer choices are: A. 2090 B.3395 C.3265 D.3266 E.3264
would it not be 1.6+2.6(n-1) ?? Remembering that you start at n=1
math: thats what I thought, but doubted myself....
Well thats what I was doing but as you can see none of my answer choices match that answer
that's because you are looking for the sum of the terms up o the 50th term
ohhhh wow silly me so I have to go back and add them all up.... sorry about that
the idea of the question i assume is for you to find the formula which does the sumation for you
can you do that with an integral of the equation?
i think to find n, you could use 50=n/2 (1.6+(n-1)2.6)
no because that would find the area under an axis of real numbers whereas you are looking to sum natural numbers
\[s \left[ n \right]=n\2(a \left[ 1 \right]+a \left[ n \right])\]
maybe?
no I don't think that is right either.....
no its not, keep trying though
Just kidding I figured it out the answer is c
1.6+49(2.6)=129 50/2(1.6+129)=3265
oh i see what you meant now by your notation! My mistake, well done :)
do any of you know or understand how to figure out a problem like this: Find the sum of the infinite series: \[\sum_{i=1}^{\infty}2(-1/4)^i\]
Thanks It took me a sec to think through it and figure it out lol maybe if I had originally read the question better lol :)
if i remember correctly there is a formula for the sum of an infinite series, first take 2 out as it is a constant and then apply the formula, (try wikipedia for it because i cannot be sure of my memory). As -1
Ok thanks

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