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anonymous

  • 5 years ago

i got 2/9x-73/9

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  1. anonymous
    • 5 years ago
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    what's the question?

  2. anonymous
    • 5 years ago
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    o crap that i thought i was replying sorry

  3. anonymous
    • 5 years ago
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    but i do have a ?

  4. anonymous
    • 5 years ago
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    what is it ^_^?

  5. anonymous
    • 5 years ago
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    write an equation of the line containing the given point and parellel to the given line... (2,-5);9x-4y=7

  6. anonymous
    • 5 years ago
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    Solve the given equation for 'y' and take the slop of that equation and the x & y values of the given point and insert them into the y=mx+b formula. Solve for b.

  7. anonymous
    • 5 years ago
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    i get that i just know how to solve for b ..this is for an online course. im so frustrated.

  8. anonymous
    • 5 years ago
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    We've already answered this question in your previous thread. I dunno why people keep making duplicate questions

  9. anonymous
    • 5 years ago
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    okay first let's re-write the function in terms of y : y =( 7-9x)/-4 = 9x/4 -7/4 then find m (slope) since it's parallel then the slope won't change: m = 9/4 now you know the equation that we use to find the function right? : y - yo = m(x - xo) substitute the points and m and solve for y ^_^ , you'l get: y +5 = 9/4(x - 2) y = 9/4x -19/2 ^_^ that's it

  10. anonymous
    • 5 years ago
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    no need to be frustrated, I'll give you a hint. When we have a parallel line then the slope never changes it'll stay the same, but when the line is perpendicular, then you must take the reciprocal of the slow ^_^

  11. anonymous
    • 5 years ago
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    slope*

  12. anonymous
    • 5 years ago
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    tarantino, did you understand it now ? :)

  13. anonymous
    • 5 years ago
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    yes thank you

  14. anonymous
    • 5 years ago
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    you are most welcome ^_^ good luck

  15. anonymous
    • 5 years ago
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    that helped alot. i did nt just want an answer im glad someone actually explained it

  16. anonymous
    • 5 years ago
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    glad you understood it :)

  17. anonymous
    • 5 years ago
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    ;)

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spraguer (Moderator)
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