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anonymous

  • 5 years ago

Indefinite integral of Sin(2x)^2(cos(2x))^2dx

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  1. amistre64
    • 5 years ago
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    integration by parts?

  2. anonymous
    • 5 years ago
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    no need :)

  3. anonymous
    • 5 years ago
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    u sub

  4. amistre64
    • 5 years ago
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    still trying to learn intergrals better... I can derive all day long :) but turning around and going back is killin' me :)

  5. anonymous
    • 5 years ago
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    Yea same here. Deriving is easy for me, going back is whats hurting me

  6. anonymous
    • 5 years ago
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    you can take :\[u = \sin^2 2u\]\[du = 4\cos^2 2u\] so : \[=1/4 \int\limits_{}^{} u du\] = 1/4 [ sin^2 2x/2] I guess :)

  7. anonymous
    • 5 years ago
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    or integration by parts if you want, but that'll be complicated ^_^

  8. anonymous
    • 5 years ago
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    orect me if I'm wrong please.

  9. anonymous
    • 5 years ago
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    correct*

  10. anonymous
    • 5 years ago
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    so, basicaly, I could "reverse" these calculations, if i use the antiderivative, right?

  11. anonymous
    • 5 years ago
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    yep ^_^, by using the antiderivative, you get the original function

  12. anonymous
    • 5 years ago
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    i knew it

  13. anonymous
    • 5 years ago
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    lol

  14. anonymous
    • 5 years ago
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    Oh! Hmm is \[ \sin ^{2}2u=\sin (2u)^{2}\]

  15. anonymous
    • 5 years ago
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    why sin^2 2u? it should be sin^2 (2x)/2 I jumped a step ahead lol

  16. anonymous
    • 5 years ago
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    yes, that is right

  17. anonymous
    • 5 years ago
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    becareful, put the brackets all over the thing (sin2u)^2 ^_^

  18. anonymous
    • 5 years ago
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    yes, brackets are LIFESAVERS, i remember how i spent 2 sleeples days trying to find a bug in my program code just to realise a pair of brackets was missing and hence the result was rong

  19. anonymous
    • 5 years ago
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    LOL! I don't like that feeling! >_<

  20. anonymous
    • 5 years ago
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    yeah, it really sucks.... debuging can be bloody annoying

  21. anonymous
    • 5 years ago
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    ._. tell me abt it

  22. anonymous
    • 5 years ago
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    haha! im doing this calculus to be a doctor...i honestly dont know when im going to integrate anything while being one though lol

  23. anonymous
    • 5 years ago
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    sorius did you get your answer? ^_^

  24. anonymous
    • 5 years ago
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    lol, mathematics is found everywhere

  25. anonymous
    • 5 years ago
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    working on it right now lol

  26. anonymous
    • 5 years ago
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    you use it to compute the area of something

  27. anonymous
    • 5 years ago
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    or anything really, not just area

  28. anonymous
    • 5 years ago
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    there is alot more :)

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