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anonymous

  • 5 years ago

midpoint approximation with 3 subintervals of the integral from 1 to 6 of exp(2sqrt(t))dt

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  1. anonymous
    • 5 years ago
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    is that what you are asking \[\int\limits_{1}^{6}e^{\2sqrt{t}}\]

  2. anonymous
    • 5 years ago
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    \[\int\limits_{1}^{6}e ^{2\sqrt{t}}\]

  3. anonymous
    • 5 years ago
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    well...since you want an approximation with 3 intervals...you first have to find the width, since midpoint approximation is cutting the graph into rectangles and adding all the areas

  4. anonymous
    • 5 years ago
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    then you find the midpoint between the intervals. and then multiply the width times the height at each midpoint. You get the answer after you add them all together

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