## anonymous 5 years ago I have one more question to whomever would love to explain to me how u solve this equation. m=7/8;(5,-7)

1. anonymous

y-(-7)=m(x-5) so you just sub in the gradient and solve

2. anonymous

i know how to write out the equation but after that im lost =(

3. anonymous

What's the question? just to find the equation?

4. anonymous

im sorry its for an online course

5. anonymous

the question is find the equation of the line having the given slope and containing the given point

6. anonymous

You sub it into the point-gradient formula, which is y-y1=m(x-x1) so using the given, sub in your gradient and your y and x-values to get: y-(-7)=(7/8)(x-5) 8(y+7)=7(x-5) 7x-8y-35-56=0 7x-8y-91=0

7. anonymous

Does that help? :I

8. anonymous

im trying to go over it

9. anonymous

You need to find the slope of the original line because the new line is parallel to it and therefore must have the same slope. Then you can write the equation for the new line using the point slope formula $y-y_0 = m(x-x_0)$ Where y0 and x0 are the y and x coordinates of a point on the line, and m is the slope of the line.

10. anonymous

where do u get 56 from

11. anonymous

8(y+7)=7(x-5) 8y+56=7x-35 0=7x-8y-35-56

12. anonymous

13. anonymous

I just threw everything over to one side..

14. anonymous

15. anonymous

83/8

16. anonymous

Ohhh you get that answer if you don't get rid of the fraction

17. anonymous

and leave 8 as the denominator

18. anonymous

right whichs is what i wasnt understandin

19. anonymous

When you leave it as a fraction: y-(-7)=(7/8)(x-5) y+7=(7x/8) - 35/8)

20. anonymous

hold on

21. anonymous

can someone type out the working, leaving it in fractional form, it's taking so long for me, ha

22. anonymous

y = (7x/8) - (91/7) confirmed

23. anonymous

$y+7=[7/8](x-5) \rightarrow y = (7x)/8 - (7*5)/8 -7$ $\rightarrow y = (7/8)x - 35/8 - 56/8 = (7/8)x - 91/8$