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anonymous
 5 years ago
Write the first five terms of the sequence defined recursively. Use the pattern to write the nth term of the sequence as a function of n. (Assume that n begins with 1.)
a[1]=5,a[k+1]=a[k]
anonymous
 5 years ago
Write the first five terms of the sequence defined recursively. Use the pattern to write the nth term of the sequence as a function of n. (Assume that n begins with 1.) a[1]=5,a[k+1]=a[k]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SO its a geometric equation I need

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the n th term is (1)^(n+1) * 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the sequence would be f(n) = 5*(1)^(n+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok well these are my options: a[n]=5n a[n]=5(1)^n a[n]=5^n a[n]=5^(n1) a[n]=5(1)^(n1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the last one. (1)^(n+1) = (1)^(n1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok I see now thanks:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the sum of the infinite series. \[\sum_{i=1}^{\infty}2(1/4)^i\] A. Undefined B. 2/3 C. 2 D.4/5 E. 2/5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ratio test shows that it converges. I cannot recall how to find what it converges to however.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is a geometric series with a = 1/4 and r = 1/4, after you factor the 2 out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The infinite sum for a geometric series is a/(1r) provided r < 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok so I would just plug those in and get my answer! Thanks so much!
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