anonymous
  • anonymous
x^2-38x+326=0 please factor
Mathematics
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anonymous
  • anonymous
x^2-38x+326=0 please factor
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[x=19\pm \sqrt{35}\]
anonymous
  • anonymous
Just apply the quadratic formula
anonymous
  • anonymous
use the quadratic formula \[x=\frac{-b \pm \sqrt {b^2-4ac}}{2a}, \] which A is the coefficient for the x^2 term B is the coefficient for the x term C is the coefficient for the x^0 term

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anonymous
  • anonymous
Yup, robtotey has the correct answer and Kynosis gives the formula
anonymous
  • anonymous
Well it looks like I will need to start this from the beginning. This is new to me so I am lost. I have a word problem. It is about a ladder leaning against a bldg. distance from bottom of ladder to bldg is 18' less than the length of the ladder. How high up the side of the bldg is the top of the ladder if that distance is 1' less than the length of the ladder
anonymous
  • anonymous
Maybe I set it up wrong. I started with \[(x-18)^2+(x-1)^2=x^2\]
anonymous
  • anonymous
Is this right?
anonymous
  • anonymous
I agree with you Geminiman
anonymous
  • anonymous
finding the roots give you the factor of the equation indirectly. because equation are in the quadratic form is (x - n) ( x- n) with n being the root you have a factored equation. of \[( x - 19+√(35)) ( x - 19-√(35))\]
anonymous
  • anonymous
ok. then I did this formula: \[x^2-36+324+x^2-2x+2=x^2\]
anonymous
  • anonymous
I get x^2 - 38x + 325 = 0
anonymous
  • anonymous
ok I got x^2338x+326=0
anonymous
  • anonymous
Then you get (x - 25)(x - 13) = 0 which is x = 25, 13
anonymous
  • anonymous
sorry typed it wrong. x^2-38x+326=0
anonymous
  • anonymous
When you took (x - 1)^2 Gem you had x^2 - 2x + 2 and it is actually x^2 - 2x + 1
anonymous
  • anonymous
ah ok that is why I got 326 instead of 325.
anonymous
  • anonymous
Thank you all for your help

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