anonymous
  • anonymous
8x/(x-8)(x-10)=9x+2
Mathematics
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anonymous
  • anonymous
8x/(x-8)(x-10)=9x+2
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Is this \(\frac{8x}{(x-8)(x-10)} = 9x+2\)?
anonymous
  • anonymous
yes
anonymous
  • anonymous
The first thing you want to do is get rid of the denominator by multiplying it to the other side.

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anonymous
  • anonymous
so the entire (x-8)(x-10)
anonymous
  • anonymous
Be careful, you can multiply the denominator to the other side provided the x is not 8 or x is not 10, otherwise we cannot just simply multiply like that
anonymous
  • anonymous
you can't multiply...
anonymous
  • anonymous
what do i do then?
anonymous
  • anonymous
8x/(x-8)(x-10)=9x+2 [8x/(x-8)(x-10)] -(9x+2) = 0 [8x -(9x+2)(x-8)(x-10)] / [(x-8)(x-10)] = 0 for the fraction on the left to be zero, the numerator must be zero. So 8x -(9x+2)(x-8)(x-10) = 0
anonymous
  • anonymous
That is the explanation, but as you can see, it has the same effect as multiply the denominator to the right side and then bring the right side to the left..
anonymous
  • anonymous
now i jsut solve>?
anonymous
  • anonymous
Yep. The key to problems that have variables in the denominator is checking your answers when you solve. If you get that \(x=8\) or \(x=10\) once you solve, you have to say that these aren't valid answers, because they would make the denominator equal zero.

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