anonymous
  • anonymous
I need help with this calculus question. Some ancient Egyptians decided to build a pyramid with a square base that measured 750 feet on a side. The height of the pyramid was 500 feet. The density of the rock used in construction was 120 pounds per cubic foot. It was assumed that the work force would remain constant. Each laborer could do 160 foot pounds of work per hour, working 12 hour days for 330 days per year for 20 years. Determine, under these conditions, the number of laborers needed to construct the pyramid.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
Is it a solid pyramid? you know, for ceremonial purposes :)
anonymous
  • anonymous
(1/3)*(750)^2*500 ft^3 * 120lbs/ft^3 * 1hr/(160lbs)/12hrs
anonymous
  • anonymous
yeah its solid

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anonymous
  • anonymous
etc
anonymous
  • anonymous
i know its a definite integral equation that is the density * volume * distance(or ht.) I just can't figure out how to represent the volume.
anonymous
  • anonymous
888 laborers
amistre64
  • amistre64
(S) A(y) dy {0,h} or something like that.... but the formula for any conelike volume is (1/3)(Base Area)(height)...
amistre64
  • amistre64
intuition would say, find the amount of rock you need, figure out how much one laborer does in the alloted time span, then multiply that by how many laborers it take to do the job..... but other than that, I dont know...
anonymous
  • anonymous
\[\int\limits_{0}^{50}(120)(volume)(y)\] the equation to find the work needed is something like this, i just can't figure out the section for volume.
anonymous
  • anonymous
50 should be 500
amistre64
  • amistre64
volume is integrated thru taking sections of the base area as it moves thru the height....
anonymous
  • anonymous
also the volume is representing the volume of a slice
amistre64
  • amistre64
each slice is x^2 dy in volume right?
amistre64
  • amistre64
and x changes with repect to height...or y
amistre64
  • amistre64
what is the slope of the face?
anonymous
  • anonymous
yeah basically, but the size of the slice changes since it is getting smaller going up
anonymous
  • anonymous
i don't know that isn't given
amistre64
  • amistre64
500/(750/2) would be a cross section of the "triangle"
amistre64
  • amistre64
the slope of a face is 500/375....might need to reduce. the equation relating that to x and y is y = -500/375(x) + 500
amistre64
  • amistre64
slope is 4/3 when reduced
amistre64
  • amistre64
x increase by 2 for every 3/4 increase in y .... if that helps
amistre64
  • amistre64
(3/2) (S) y dy {0,500} = (3/4) y^2 {0,500} 500^2 = 250000(3/4) = 750000/4 = 187500 that matches 500(750)/2 = 187500 for a flat area..... not sure how it helps tho :)
amistre64
  • amistre64
x^2 is the area of a normal base and it changes with respect to "y" at a rate of (3/2)(y) dy ?? It looks right, but this is still shakey ground fer me :)
anonymous
  • anonymous
yeah i think ive gotten it now, thanks.
amistre64
  • amistre64
if I messed up anything, youlet me know :)

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