Determine which one of the ordered pairs below is a solution of the system of linear inequalities. x>-3 y>-1 y≤4-(2(x)/3) Answer options: (-1,-9) (-7, -9) (2, 2) (-1, 5) (3, -3)

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Determine which one of the ordered pairs below is a solution of the system of linear inequalities. x>-3 y>-1 y≤4-(2(x)/3) Answer options: (-1,-9) (-7, -9) (2, 2) (-1, 5) (3, -3)

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ok. so let's begin. since x > -3, this eliminates the (-7,-9) option. so we are left with (-1,-9); (2,2); (-1,5); (3, -3) now applying the equality y > -1 this eliminates the first, and the last option because y = -9 and -3. so now we have left (2,2) and (-1,5) now just plug in the x value and see if it satisfies equaltiy using the third equation.so y <= 4 - 2x/3 sooo 4 - (2*2/3 = 4 - (4/3) = (12/3) - (4/3) = (8/3). 2 <= 8/3 ? YES! this works for (2,2) now let's check it for (-1, 5) so 5 <= 4 - (2* -1)/3 = 4 - (-2/3) = 4+(2/3) = (12/3) + (2/3) = (14/3). and 14/3 is not less than 5. so the ordered pair that is satisfies it is (2,2)
Ok so I wa right when i did it the first time somehow when I put the (-1,5) it worked too but I see where I made my mistake! Thank you so much!
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