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^^
if any

u should find that the maximum is when t=175/32

yes

So there is no interval during which the projectile would be visible at ground level, right?

when you solve the equation given for part a greater than 240...it will never exist

sorry

wait...i just realized that the equation is given from ground level

so the maximum height the is 238.51 above ground level

so part a is written wrong

−16t2+175t−240≥0

you should be solving −16t2+175t−240≥0 for part a

\[H_\max=V_i/t_o+s(t_0), t_0=175/32\]

\[V_i*t_0\]*

I am making so many mistakes :(

for part a you should get t needs to be between 1.6078 and 9.3297

dont worry....i misread the problem at first too

its not above ground until 1.6078