anonymous
  • anonymous
rational expression equations : (3/2k^2) - (1/2k)=(k+2)/(k^2)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
(6-k)/(2k^2) = [2(k+2)]/(2k^2) compare the numerator, you get 6-k = 2k +4 and you can get you k easily
anonymous
  • anonymous
sorry, i mislook
anonymous
  • anonymous
it is (3-k) instead of 6-k

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anonymous
  • anonymous
and what do i do next do i mulipy the first fractions of the problem or the (3-k)/(2k^2)=2(k+2)/(2k^2)

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