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anonymous
 5 years ago
can anyone help me with proof that det(A)=det(A) for nxn matrices?
anonymous
 5 years ago
can anyone help me with proof that det(A)=det(A) for nxn matrices?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can find it in any Linear Algebra book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I guess I'll look harder

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which Linear Algebra book are you refering?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know we are using the scaling method three times which gives us det(B)=s(det(A))

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0you can find all you need here: http://en.wikipedia.org/wiki/Determinant Just use \[\det (αA) = α^n \det (A) \] and you will see your conjecture does only hold for even numbers n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so does 1(det(A)=det(A)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh yes...I get it now, I overlooked that formula, the exponent threw me off, thakns

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are many ways to prove it, depends on how the determinant is defined. In beginning linear algebra book, the determinant is not defined using the Leibniz formula. In that case, there is another proof
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