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anonymous
 5 years ago
I am trying to evaluate the intergral [(ax^3bx^7)/x^(1/2)] and I'm not given an interval. I'm asuming it is a through b. understand the process of integrals, I'm just getting caught up with the algebra......
anonymous
 5 years ago
I am trying to evaluate the intergral [(ax^3bx^7)/x^(1/2)] and I'm not given an interval. I'm asuming it is a through b. understand the process of integrals, I'm just getting caught up with the algebra......

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when no limit of integration is given, that is called an indefinite integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does it mean to have to evaluate the intergral ????????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So simplify (ax^3bx^7)/x^(1/2) to becomes ax^(7/2)  bx^(15/2) Integrate it will give (2/9)ax^(9/2)  (2/17)bx^(17/2) + C, where C is a constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got a^6  b ^14 ,, i simpliefied, istha evaluating the intergral,,, or what is the intergral??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I had to go to class. Indefinite Integral, yes you are right sklee. Thank you sklee and MiL3ARN3R. I am getting a couple different answers here. I will be back online later. Thanks again.
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