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anonymous

  • 5 years ago

22r^3s^2 over 11r^2s^-3

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  1. amistre64
    • 5 years ago
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    22 r^3 s^2 --- --- ----- subtract bottom exponents from top exponents 11 r^2 s^-3 2 r^(3-2) s^(2--3) = 2 r s^5

  2. amistre64
    • 5 years ago
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    2 negatives makes a positive, I dont care where your at :)

  3. anonymous
    • 5 years ago
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    alright lol im really really bad at algebra

  4. anonymous
    • 5 years ago
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    I got (2r) (1/2^-5)

  5. amistre64
    • 5 years ago
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    mit: then you musta did something wrong :)

  6. anonymous
    • 5 years ago
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    i just divie the s over its 2s which gave me 1/2 ^5 ,do you know where I went rong

  7. amistre64
    • 5 years ago
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    cant say fer sure, but I got an inkling of an idea... its the "s" variables that are catching you up right?

  8. amistre64
    • 5 years ago
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    what happens when we do this: 2-(-3) = ??

  9. anonymous
    • 5 years ago
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    my bad , now I know my abc's ,, i was looking at the s^3 as 2s^3 because of 11r^2 ,

  10. amistre64
    • 5 years ago
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    and I think youre seeing the problem wrong; it aint 2s that we are working with.. yeah, you figured that out :)

  11. anonymous
    • 5 years ago
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    im knew here

  12. amistre64
    • 5 years ago
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    new or old; at least your here :)

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