m^-2 n^-5 0ver (m^4 n^3)^-1

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m^-2 n^-5 0ver (m^4 n^3)^-1

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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do you mean \[(m ^{-2}n ^{-5})/(m ^{4}n ^{3})^{-1}\]
yes
the exponent -1 on the bottom makes everything on the bottom move to the top

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Other answers:

then you just combine like terms...
so the m^-2 and the m^4 becomes m^2
since \[x ^{a}x ^{b}=x ^{a+b}\]
can you try to combine the n's
yeah
but its a negative exponet and you cant have a negative exponet in your final answer
then the negative exponent will move back to the denominator
so the final answer should be m^2/n^2
ohhhhh

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