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anonymous

  • 5 years ago

m^-2 n^-5 0ver (m^4 n^3)^-1

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  1. anonymous
    • 5 years ago
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    do you mean \[(m ^{-2}n ^{-5})/(m ^{4}n ^{3})^{-1}\]

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    the exponent -1 on the bottom makes everything on the bottom move to the top

  4. anonymous
    • 5 years ago
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    then you just combine like terms...

  5. anonymous
    • 5 years ago
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    so the m^-2 and the m^4 becomes m^2

  6. anonymous
    • 5 years ago
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    since \[x ^{a}x ^{b}=x ^{a+b}\]

  7. anonymous
    • 5 years ago
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    can you try to combine the n's

  8. anonymous
    • 5 years ago
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    yeah

  9. anonymous
    • 5 years ago
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    but its a negative exponet and you cant have a negative exponet in your final answer

  10. anonymous
    • 5 years ago
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    then the negative exponent will move back to the denominator

  11. anonymous
    • 5 years ago
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    so the final answer should be m^2/n^2

  12. anonymous
    • 5 years ago
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    ohhhhh

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