anonymous
  • anonymous
m^-2 n^-5 0ver (m^4 n^3)^-1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
do you mean \[(m ^{-2}n ^{-5})/(m ^{4}n ^{3})^{-1}\]
anonymous
  • anonymous
yes
anonymous
  • anonymous
the exponent -1 on the bottom makes everything on the bottom move to the top

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anonymous
  • anonymous
then you just combine like terms...
anonymous
  • anonymous
so the m^-2 and the m^4 becomes m^2
anonymous
  • anonymous
since \[x ^{a}x ^{b}=x ^{a+b}\]
anonymous
  • anonymous
can you try to combine the n's
anonymous
  • anonymous
yeah
anonymous
  • anonymous
but its a negative exponet and you cant have a negative exponet in your final answer
anonymous
  • anonymous
then the negative exponent will move back to the denominator
anonymous
  • anonymous
so the final answer should be m^2/n^2
anonymous
  • anonymous
ohhhhh

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