anonymous
  • anonymous
factor out the trinomial. h=-2tsquared+87t+90
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
well i know from there what you do is \[-(2t ^{2}-87t-90)\] then you multiply 90 and 2t squared which gives you -180 then what you have to do is think what times what vies me 180 but also when u add/subtract them it gives you 87 and i dont know those two number
anonymous
  • anonymous
Just use the quadratic equation \[t = [-b \pm \sqrt{b^2-4ac}]/2a\] Where a=-2, b=87, c=90. That will give you your two values for t when h=0 allowing you to rewrite the equation as \[h = (t-t_1)(t-t_2)\]
anonymous
  • anonymous
i never learned that i just need two number that multiply and equal 180 but when u add/subtract those two numbers in equals 16

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anonymous
  • anonymous
Are you sure the middle term isn't 88t?
anonymous
  • anonymous
im sure
anonymous
  • anonymous
Then you don't get nice numbers. If it were 88t you'd have: h=-(2t+2)(t-45) As it is here, you get h=(t + 1.0109863582402774)(t-44.510986358240274)
anonymous
  • anonymous
oh woah i will just ask my teacher tomorrow
anonymous
  • anonymous
thank you though!
anonymous
  • anonymous
oh and also what times what equals 1536 but when u add/subtract them it eguals -16

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