## anonymous 5 years ago factor out the trinomial. h=-2tsquared+87t+90

1. anonymous

well i know from there what you do is $-(2t ^{2}-87t-90)$ then you multiply 90 and 2t squared which gives you -180 then what you have to do is think what times what vies me 180 but also when u add/subtract them it gives you 87 and i dont know those two number

2. anonymous

Just use the quadratic equation $t = [-b \pm \sqrt{b^2-4ac}]/2a$ Where a=-2, b=87, c=90. That will give you your two values for t when h=0 allowing you to rewrite the equation as $h = (t-t_1)(t-t_2)$

3. anonymous

i never learned that i just need two number that multiply and equal 180 but when u add/subtract those two numbers in equals 16

4. anonymous

Are you sure the middle term isn't 88t?

5. anonymous

im sure

6. anonymous

Then you don't get nice numbers. If it were 88t you'd have: h=-(2t+2)(t-45) As it is here, you get h=(t + 1.0109863582402774)(t-44.510986358240274)

7. anonymous

oh woah i will just ask my teacher tomorrow

8. anonymous

thank you though!

9. anonymous

oh and also what times what equals 1536 but when u add/subtract them it eguals -16