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anonymous

  • 5 years ago

factor out the trinomial. h=-2tsquared+87t+90

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  1. anonymous
    • 5 years ago
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    well i know from there what you do is \[-(2t ^{2}-87t-90)\] then you multiply 90 and 2t squared which gives you -180 then what you have to do is think what times what vies me 180 but also when u add/subtract them it gives you 87 and i dont know those two number

  2. anonymous
    • 5 years ago
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    Just use the quadratic equation \[t = [-b \pm \sqrt{b^2-4ac}]/2a\] Where a=-2, b=87, c=90. That will give you your two values for t when h=0 allowing you to rewrite the equation as \[h = (t-t_1)(t-t_2)\]

  3. anonymous
    • 5 years ago
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    i never learned that i just need two number that multiply and equal 180 but when u add/subtract those two numbers in equals 16

  4. anonymous
    • 5 years ago
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    Are you sure the middle term isn't 88t?

  5. anonymous
    • 5 years ago
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    im sure

  6. anonymous
    • 5 years ago
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    Then you don't get nice numbers. If it were 88t you'd have: h=-(2t+2)(t-45) As it is here, you get h=(t + 1.0109863582402774)(t-44.510986358240274)

  7. anonymous
    • 5 years ago
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    oh woah i will just ask my teacher tomorrow

  8. anonymous
    • 5 years ago
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    thank you though!

  9. anonymous
    • 5 years ago
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    oh and also what times what equals 1536 but when u add/subtract them it eguals -16

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spraguer (Moderator)
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