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anonymous

  • 5 years ago

what times what equals 1536 but when u add/subtract them it eguals -16

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  1. anonymous
    • 5 years ago
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    Set up 2 equations: x*y=1536 x+y=-16 (based on your wording?) You know that x = 1536/y, plug it into the second equation and solve for y. Then take that value and get the value for x.

  2. anonymous
    • 5 years ago
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    i dont get it

  3. anonymous
    • 5 years ago
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    what are the two numbers

  4. anonymous
    • 5 years ago
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    x and y are just what we call the first and second numbers that you're working with. When you plug that new value of x into the second equation, you get 1536/y + y = -16. You can now multiply every term by y to eliminate the fraction, and solve the quadratic to get the values of y.

  5. anonymous
    • 5 years ago
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    i still dont get it? i never learned that way?^ can you please just tell me the two number and i can work the rest of the problem on from there

  6. anonymous
    • 5 years ago
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    u need to use x-y=-6 because if u use x+y=-16, the quadratic u get wont have real solution

  7. anonymous
    • 5 years ago
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    can someone please just tell me the two numbers

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spraguer (Moderator)
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