## anonymous 5 years ago Equation Simplification Help Please...

1. anonymous

$(2(k+1)!/4^{k+1})\times(4^{k}/(2k)!)$

2. anonymous

4^k/4^(k+1) simplifies to 1/4, which means that your expression simplifies to (k+1)!/(2(2k)!).

3. anonymous

Sorry! Just realised I missed out a pair of brackets!$((2(k+1))!/4^{k+1})\times(4^{k}/(2k)!)$

4. anonymous

is it: $(2(k+1))!/4(2k)!$

5. anonymous

$[2(k+1)]! = [2k+2]*[2k+1]*[2k]!$ See if that doesn't help simplify.

6. anonymous

I think I get (4k^2+5k+2)/4

7. anonymous

Close. Should be $(2k+1)(k+1)/2 = (2k^2 + 3k + 1)/2$

8. anonymous

How did you get that? Aren't we left with the [2k+2]∗[2k+1] on top

9. anonymous

yes, and 4 on bottom. You can divide 2k+2 by 2, leaving (k+1)*(2k+1) on top and 2 on the bottom.

10. anonymous

Haha! What's wrong with me today... That was obvious! Thanks for all your help mate. Any chance you could send me your email or something so I can contact you when I don't find you here? You've been a massive help to me today!

11. anonymous
12. anonymous

Let me know when you get it. and send me an email.

13. anonymous

got it mate.

14. anonymous

Send me a quick email and I'll delete the dpaste.

15. anonymous

Sent.