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anonymous
 5 years ago
Equation Simplification Help Please...
anonymous
 5 years ago
Equation Simplification Help Please...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(2(k+1)!/4^{k+1})\times(4^{k}/(2k)!)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04^k/4^(k+1) simplifies to 1/4, which means that your expression simplifies to (k+1)!/(2(2k)!).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry! Just realised I missed out a pair of brackets!\[((2(k+1))!/4^{k+1})\times(4^{k}/(2k)!)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it: \[(2(k+1))!/4(2k)!\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[[2(k+1)]! = [2k+2]*[2k+1]*[2k]!\] See if that doesn't help simplify.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I get (4k^2+5k+2)/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Close. Should be \[(2k+1)(k+1)/2 = (2k^2 + 3k + 1)/2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get that? Aren't we left with the [2k+2]∗[2k+1] on top

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, and 4 on bottom. You can divide 2k+2 by 2, leaving (k+1)*(2k+1) on top and 2 on the bottom.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha! What's wrong with me today... That was obvious! Thanks for all your help mate. Any chance you could send me your email or something so I can contact you when I don't find you here? You've been a massive help to me today!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let me know when you get it. and send me an email.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Send me a quick email and I'll delete the dpaste.
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