anonymous
  • anonymous
Integrate b=0 a=2 x(x-3) dx=??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\int\limits_{0}^{2} x(x-3) dx=?\]
anonymous
  • anonymous
Multiply it out and integrate term by term. \[= \int\limits_{0}^{2} x^2 - 3x\ dx\]
anonymous
  • anonymous
(x^3) -(3x^2)/2 and then use the integration limits

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anonymous
  • anonymous
(x^3)/3 -(3x^2)/2 *
anonymous
  • anonymous
i know the answer is -10/3 but i cant seem to get it. Idk what im missing
anonymous
  • anonymous
ok so we have (2^3)/3 = 8/3 and 3(2^2)/2 = 3*4/3 = 4 so for the limit 2 we get 8/3 - 4 = and limit 0 will just be 0 for x so it will turn out to be 0. so final answer is 8/3 -4 = 8/3 - 12/3 = -4/3
anonymous
  • anonymous
woops hold on lol error
anonymous
  • anonymous
the answer is -10/3 according to the book. I think where you have 4, it should be 6 right? that works out i think
anonymous
  • anonymous
it shuld be 8/3 - 6 = 8/3 - 18/6 = -10/3
anonymous
  • anonymous
8/3 - 18/3 = -10/3 *
anonymous
  • anonymous
thank you for the help... im new to the site... anybody want to give me a quick overview?
anonymous
  • anonymous
in general, we post doubts and other people try to help...
anonymous
  • anonymous
i see that... i dont know how i have never heard of this site... it would have been a lifesaver for calculus this semester
anonymous
  • anonymous
hahaha!

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