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anonymous
 5 years ago
How do I go about solving a nonhorizontally launched projectile problem ("launched [x] m/s [x] degrees above the horizontal") if it includes a starting height (cliff)?
anonymous
 5 years ago
How do I go about solving a nonhorizontally launched projectile problem ("launched [x] m/s [x] degrees above the horizontal") if it includes a starting height (cliff)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You will have equations for both the x (horizontal) and y (vertical) motion. For each direction you need the initial velocity, the acceleration and the initial position. You get the xcomponent of the initial velocity by using the cosine of the firing angle [Vx = V cos (angle)] and the ycomponent of the initial velocity using the sin of the firing angle. You can usually let the initial x position be zero. The initial y position is usually the height of the cliff. There is usually no acceleration in the xdirection unless there is wind resistance, but there will be acceleration due to gravity in the y direction. The big deal is to figure out what quantities are positive or negative. Here's the deal: if you made the positive y direction up, make the acceleration due to gravity negative (since it is down and down is negative); if you made the positive y direction downward, make the acceleration due to gravity positive (since you defined down as positive). Careful  consider the big picture: if up is positive, and the projectile's initial velocity is down (cannon aimed downward), then you must make the initial yvelocity negative as well as making the acceleration due to gravity negative. Work either the x or y equation until you need a "missing" variable  like time. You switch to the other dimension to get the missing variable... then plug it back in to the equation needing that info.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Awesome; thank you so much!
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