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anonymous

  • 5 years ago

sqrt (16x- 16) + sqrt (25x^3- 25x^2)

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  1. anonymous
    • 5 years ago
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    my teacher told us not to like mess with the binomials so im confused

  2. anonymous
    • 5 years ago
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    You can factor coefficients out of the first inside expression, so you get: sqrt(16(x-1)) - sqrt(25x^2(x-1)). The 16 in the first term comes to be a 4 on the outside. The 25x^2 inside the second term comes to be a 5x on the outside. 4sqrt(x-1)-5x*sqrt(x-1) And you can simplify by factoring out the sqrt(x-1): sqrt(x-1)*(4-5x).

  3. anonymous
    • 5 years ago
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    im so confused

  4. anonymous
    • 5 years ago
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    Do you get that (16x-16)=16(x-1)?

  5. anonymous
    • 5 years ago
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    o k now i get it wen u put it simplerr

  6. anonymous
    • 5 years ago
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    But 16 is a square so you can bring out it's root

  7. anonymous
    • 5 years ago
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    but its connected to a binomial so wich one of them...or both and 25 is also a square connected to a binomial in the laast half of the problem

  8. anonymous
    • 5 years ago
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    Well, we rewrite \(\sqrt{16(x-1)}\) as \(\sqrt{16}\sqrt{x-1}\) and simplify.

  9. anonymous
    • 5 years ago
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    Can you rewrite the second half now?

  10. anonymous
    • 5 years ago
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    yse so the answer is 5x + 4 sqrt x-1?

  11. anonymous
    • 5 years ago
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    (4-5x)

  12. anonymous
    • 5 years ago
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    and i knock off the sqrt x-1?

  13. anonymous
    • 5 years ago
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    no, no, no, just replace the 5x+4 with (4-5x)

  14. anonymous
    • 5 years ago
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    o okay

  15. anonymous
    • 5 years ago
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    do u mean 4 + 5x

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