anonymous
  • anonymous
sqrt (16x- 16) + sqrt (25x^3- 25x^2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
my teacher told us not to like mess with the binomials so im confused
anonymous
  • anonymous
You can factor coefficients out of the first inside expression, so you get: sqrt(16(x-1)) - sqrt(25x^2(x-1)). The 16 in the first term comes to be a 4 on the outside. The 25x^2 inside the second term comes to be a 5x on the outside. 4sqrt(x-1)-5x*sqrt(x-1) And you can simplify by factoring out the sqrt(x-1): sqrt(x-1)*(4-5x).
anonymous
  • anonymous
im so confused

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anonymous
  • anonymous
Do you get that (16x-16)=16(x-1)?
anonymous
  • anonymous
o k now i get it wen u put it simplerr
anonymous
  • anonymous
But 16 is a square so you can bring out it's root
anonymous
  • anonymous
but its connected to a binomial so wich one of them...or both and 25 is also a square connected to a binomial in the laast half of the problem
anonymous
  • anonymous
Well, we rewrite \(\sqrt{16(x-1)}\) as \(\sqrt{16}\sqrt{x-1}\) and simplify.
anonymous
  • anonymous
Can you rewrite the second half now?
anonymous
  • anonymous
yse so the answer is 5x + 4 sqrt x-1?
anonymous
  • anonymous
(4-5x)
anonymous
  • anonymous
and i knock off the sqrt x-1?
anonymous
  • anonymous
no, no, no, just replace the 5x+4 with (4-5x)
anonymous
  • anonymous
o okay
anonymous
  • anonymous
do u mean 4 + 5x

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