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anonymous
 5 years ago
determine the derivative y' at the point (1,0)
y=ln(x^2+y^2)
anonymous
 5 years ago
determine the derivative y' at the point (1,0) y=ln(x^2+y^2)

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0[ln(inside)]'=(inside)'/inside

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' = (2x + 2yy')/(x^2+y^2) right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' = 2x/(x^2 +y^2  2x) .. if i did it right...which is a big if :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that last 2x should be a 2y...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' = 2x/(x^2 + y^2  2y) (x=1,y=0) y' = 2/(1) = 2 ??
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