## anonymous 5 years ago From a boat on the lake, the angle of elevation to the top of a cliff is 16°36'. If the base of the cliff is 1892 feet from the boat, how high is the cliff (to the nearest foot)

1. anonymous

$\tan(16^o32')=\frac{h}{1892} \rightarrow h = 1892 \tan (16^o32') \approx 562ft$to nearest foot.

2. anonymous

i cant see the rest

3. anonymous

Refresh your screen. It should all be visible.

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