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anonymous

  • 5 years ago

Write an equation of the line containing the given point and parellel to the given line (6,9); x+8y=3

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  1. amistre64
    • 5 years ago
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    parallel lines have the same slope; they lean in the same way...

  2. amistre64
    • 5 years ago
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    and I think they might even have the same equation; but just a different answer; a different "right hand side"... but I would have to take that with a grain of salt.

  3. anonymous
    • 5 years ago
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    Find the slope for that line either by converting into slope intercept or point slope. Then use that same slope and the point you are given and plug it into the point slope formula \[y-y_0 = m(x-x_0)\]

  4. anonymous
    • 5 years ago
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    Where m is the slope of the original line and x0 and y0 are the x and y coordinates of your point

  5. amistre64
    • 5 years ago
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    y = -x/8 + 3/8 y = -x/8 + b (x=6,y=9) 9 = -(6)/8 + b 9 = -3/4 + b 9+3/4 = b 39/4 = b y = -x/8 + 78/8 x+8y = 78 double check: (x=6,y=9) 6+8(9) = 78 6 + 72 = 78 78 = 78 good

  6. amistre64
    • 5 years ago
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    so far, same equation; plug in your x,y and see what the RHS is for a parallel line.... needs more research tho :)

  7. amistre64
    • 5 years ago
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    Does that make sense luv?

  8. anonymous
    • 5 years ago
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    That seems very complicated. \[x+8y=3 \rightarrow y=1/8x + 3/8 \rightarrow slope\ is\ 1/8\] \[New line is y-9 = 1/8(x-6) -> y = x/8 -6/8 +9 \rightarrow 8y -x = 66\]

  9. anonymous
    • 5 years ago
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    Bleh formatting

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