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anonymous
 5 years ago
Write an equation of the line containing the given point and parellel to the given line (6,9); x+8y=3
anonymous
 5 years ago
Write an equation of the line containing the given point and parellel to the given line (6,9); x+8y=3

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0parallel lines have the same slope; they lean in the same way...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and I think they might even have the same equation; but just a different answer; a different "right hand side"... but I would have to take that with a grain of salt.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the slope for that line either by converting into slope intercept or point slope. Then use that same slope and the point you are given and plug it into the point slope formula \[yy_0 = m(xx_0)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where m is the slope of the original line and x0 and y0 are the x and y coordinates of your point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = x/8 + 3/8 y = x/8 + b (x=6,y=9) 9 = (6)/8 + b 9 = 3/4 + b 9+3/4 = b 39/4 = b y = x/8 + 78/8 x+8y = 78 double check: (x=6,y=9) 6+8(9) = 78 6 + 72 = 78 78 = 78 good

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so far, same equation; plug in your x,y and see what the RHS is for a parallel line.... needs more research tho :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make sense luv?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That seems very complicated. \[x+8y=3 \rightarrow y=1/8x + 3/8 \rightarrow slope\ is\ 1/8\] \[New line is y9 = 1/8(x6) > y = x/8 6/8 +9 \rightarrow 8y x = 66\]
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