Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

what is the aproximate volume of a cone shaped party hat with a base whose circumference is 25.12 inches and height is 8 inches

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

volume of cone is 1/3 pi r^2 h 2pi r=25.12 r=25.12/2pi r=4.0
vol= 1/3 * pi* (4.0)^2 *8 =134.1cubic inches
oh bt i have multiple coice and a.401.92 b.33.49 c.133.97 d.535.89 so whivh one would it be

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

C
k thanx
so beens its c right?
yeah
how is it c though if u told me that its 134.1
if you HAVE to choose...there will be a margin of error when calculating
whenever u round of things and continue calculatinbg with the figures that happens...pi by it sely is a rounded figure...i used 3.142
oh okay now i get well thanx .
ok
can you try to answer my friends question by smiley75 because we have the same questions

Not the answer you are looking for?

Search for more explanations.

Ask your own question