anonymous
  • anonymous
Evaluating Indefinite Integrals
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\int\limits 2(2x+4)^5dx\] u=2x+4
anonymous
  • anonymous
du=2dx \[\int\limits_{}^{}u^{5}du\]
anonymous
  • anonymous
He's doing well, let him continue. :P

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i got that far lol im stuck with the rest... I know the answer is 1/6(2x+4)^6+c
anonymous
  • anonymous
Okay, so you've got that u = 2x+4. du = 2 * dx, right? Now, put it in terms of dx : dx = du/2.
anonymous
  • anonymous
In your original integral, replace all (2x+4) with u, and all dx with du/2. The original 2 in front will cancel out, and you'll be left integrating u^5 du. :) Integrate, and plug the value for u back into it.
anonymous
  • anonymous
im not sure if i am supposed to distribute the first "2" or put it in front of the integral
anonymous
  • anonymous
The two can stay inside or outside of the integral, but it would make life a lot easier to not distribute it through your polynomial. :P Do you understand the substitution?
anonymous
  • anonymous
yep... i have \[\int\limits u^5 du \]
anonymous
  • anonymous
There you go. :) Integrate now, and when you're finished, all you have to do is sub 2x+4 back inside for u.
anonymous
  • anonymous
thats where i am having trouble lol i HATE integration... is it u^6/6 +c?
anonymous
  • anonymous
Yep, that's it.
anonymous
  • anonymous
wonderful! i got it now... plug 2x+4 in for x and solve! thank you so much!
anonymous
  • anonymous
Power rule for integration: \[\int\limits \ \ x^n \ dx = \frac{x^{n+1}}{n+1}+c\]
anonymous
  • anonymous
i wish this site had a friends feature lol youd be a lifesaver... literally (not like me)
anonymous
  • anonymous
Lol, no problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.