## anonymous 5 years ago Noel Womack scored 87,96,86,92, and 93 in English 101. What must he score on the last test to earn an average score of 92?

The arithmetic average of a set of n numbers is $\frac{a_1+a_2+...+a_n}{n}$You have the situation where you want an average of 92, and you know, in the end, you'll have six scores (so n will be 6), and you have the first five terms. All you need to do is substitute in and solve:$92=\frac{87+96+86+92+93+x}{6} =\frac{454+x}{6}$Solve for x:$92 \times 6 -454 =x \rightarrow x=98$