A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

Find the point on the line 8x+7y-2=0 which is closest to the point (-6,-4).

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=(2/7)-(8/7)x The point (-6,-4) should be located on a line perpendicular to the original equation Thus use use the negative inverse of the slope m (which is -(8/7) and make it +(7/8)) Plug in (-6,-4) into the general line equation: y=mx+b and solve for b set the two equations equal to each other and you get the closest point. To find the distance between use: distance formula d=sqrt((x2-x1)^2+(y2-y1)^2)

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Remember, the shortest distance between a line and a point is a perpendicular line between the point and the other point on the line.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.