anonymous
  • anonymous
how do we tell the values of a and b in the following equation: ax + by = 1 they provide a graph with a line angled down and to the right like so \ the question is asking which of the following must be true: 1: a>0 and b< 0 2: a >0 and b > 0 3: a<0 and b <0 4: a <0 and b>0 5: a = 0 and b>0
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
when x is 0 b(y)=1... b = 1/y
amistre64
  • amistre64
a = 1/x when y = 0; you got 2 points now... just dont know what to do with them next :)
anonymous
  • anonymous
in the graph, where the line cross x=0?

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anonymous
  • anonymous
to the right of the y axis
anonymous
  • anonymous
and the y intercept would be 1/b right?
amistre64
  • amistre64
(0,1/y) and (1/x, 0) slope is equal to diff in y over diff in x (1/y) - 0 1/y -------- = ---- 0 - (1/x) -1/x
amistre64
  • amistre64
y = -x/y + 1
anonymous
  • anonymous
so the correct answer is (4) amistre, value of a is <0.
amistre64
  • amistre64
it is?...lol yay!!!
amistre64
  • amistre64
i got lost in my ramblings :)
anonymous
  • anonymous
lol!
anonymous
  • anonymous
ok, so how do you know whether b is positive or negative?
amistre64
  • amistre64
b = 1/y y = -x/y + 1/y :) b is positive cause its where it hits the y axis.... i think
anonymous
  • anonymous
another question: the graph pass up or down y=0??
amistre64
  • amistre64
x + y^2 = 1 is what i think i get.... does that make sense?
anonymous
  • anonymous
y intercept is positive
amistre64
  • amistre64
a=1 and b=y ..... maybe :)
anonymous
  • anonymous
Rewrite y=(-a/b)x + (c/b) if c=1 and the line cross positive y axxis, b must be positive!
anonymous
  • anonymous
c=1 *** from text..
anonymous
  • anonymous
did you get?
anonymous
  • anonymous
ohhhh, yes i get it!
anonymous
  • anonymous
thank you so much!
anonymous
  • anonymous
you're welcome! I need to sleep.. see ya!

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