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anonymous
 5 years ago
how do we tell the values of a and b in the following equation: ax + by = 1
they provide a graph with a line angled down and to the right like so \
the question is asking which of the following must be true:
1: a>0 and b< 0
2: a >0 and b > 0
3: a<0 and b <0
4: a <0 and b>0
5: a = 0 and b>0
anonymous
 5 years ago
how do we tell the values of a and b in the following equation: ax + by = 1 they provide a graph with a line angled down and to the right like so \ the question is asking which of the following must be true: 1: a>0 and b< 0 2: a >0 and b > 0 3: a<0 and b <0 4: a <0 and b>0 5: a = 0 and b>0

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when x is 0 b(y)=1... b = 1/y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a = 1/x when y = 0; you got 2 points now... just dont know what to do with them next :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the graph, where the line cross x=0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to the right of the y axis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the y intercept would be 1/b right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(0,1/y) and (1/x, 0) slope is equal to diff in y over diff in x (1/y)  0 1/y  =  0  (1/x) 1/x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the correct answer is (4) amistre, value of a is <0.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got lost in my ramblings :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so how do you know whether b is positive or negative?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b = 1/y y = x/y + 1/y :) b is positive cause its where it hits the y axis.... i think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0another question: the graph pass up or down y=0??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x + y^2 = 1 is what i think i get.... does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y intercept is positive

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a=1 and b=y ..... maybe :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Rewrite y=(a/b)x + (c/b) if c=1 and the line cross positive y axxis, b must be positive!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're welcome! I need to sleep.. see ya!
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