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- anonymous

how do we tell the values of a and b in the following equation: ax + by = 1
they provide a graph with a line angled down and to the right like so \
the question is asking which of the following must be true:
1: a>0 and b< 0
2: a >0 and b > 0
3: a<0 and b <0
4: a <0 and b>0
5: a = 0 and b>0

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- anonymous

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- amistre64

when x is 0 b(y)=1... b = 1/y

- amistre64

a = 1/x when y = 0; you got 2 points now... just dont know what to do with them next :)

- anonymous

in the graph, where the line cross x=0?

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- anonymous

to the right of the y axis

- anonymous

and the y intercept would be 1/b right?

- amistre64

(0,1/y) and (1/x, 0)
slope is equal to diff in y over diff in x
(1/y) - 0 1/y
-------- = ----
0 - (1/x) -1/x

- amistre64

y = -x/y + 1

- anonymous

so the correct answer is (4)
amistre, value of a is <0.

- amistre64

it is?...lol yay!!!

- amistre64

i got lost in my ramblings :)

- anonymous

lol!

- anonymous

ok, so how do you know whether b is positive or negative?

- amistre64

b = 1/y
y = -x/y + 1/y :) b is positive cause its where it hits the y axis.... i think

- anonymous

another question: the graph pass up or down y=0??

- amistre64

x + y^2 = 1 is what i think i get.... does that make sense?

- anonymous

y intercept is positive

- amistre64

a=1 and b=y ..... maybe :)

- anonymous

Rewrite
y=(-a/b)x + (c/b)
if c=1 and the line cross positive y axxis, b must be positive!

- anonymous

c=1 *** from text..

- anonymous

did you get?

- anonymous

ohhhh, yes i get it!

- anonymous

thank you so much!

- anonymous

you're welcome! I need to sleep.. see ya!

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