anonymous
  • anonymous
f(x) = 2x2 - 12x + 2 [0, 8] find the absolute max and absolute min of f on the given interval
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Take the derivative.=> 4x -12 set it equal to 0 to find critical points. 0 = 4x -12 => x = 3
anonymous
  • anonymous
f'(x)=4x-12---> x= 3 f(0)=2 f(8)=2(64)-12(8)+2=....
anonymous
  • anonymous
Try x=3, and our boundary points 0 , and 8 into the original equation. and figure out which gives the biggest value and which gives the smallest value.

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