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anonymous

  • 5 years ago

f(x) = 2x2 - 12x + 2 [0, 8] find the absolute max and absolute min of f on the given interval

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  1. anonymous
    • 5 years ago
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    Take the derivative.=> 4x -12 set it equal to 0 to find critical points. 0 = 4x -12 => x = 3

  2. anonymous
    • 5 years ago
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    f'(x)=4x-12---> x= 3 f(0)=2 f(8)=2(64)-12(8)+2=....

  3. anonymous
    • 5 years ago
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    Try x=3, and our boundary points 0 , and 8 into the original equation. and figure out which gives the biggest value and which gives the smallest value.

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