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anonymous
 5 years ago
evaluate cos(arcsin(3/5)  arccos(3/5))
anonymous
 5 years ago
evaluate cos(arcsin(3/5)  arccos(3/5))

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the double angle formula for cosine and definition of inverses. So,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cos (\sin^{1}\frac{3}{5}\cos^{1}\frac{3}{5})\]\[=\cos (\sin^{1}\frac{3}{5}) \cos(\cos^{1}\frac{3}{5})+\sin(\sin^{1}\frac{3}{5})\sin(\cos^{1}\frac{3}{5})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[=\sqrt{1\sin^2(\sin^{1}\frac{3}{5}})\frac{3}{5}+\frac{3}{5}\sqrt{1\sin^2(\sin^{1}\frac{3}{5})}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[=\sqrt{1\left( \frac{3}{5} \right)^2}\frac{3}{5}+\frac{3}{5}\sqrt{1\left( \frac{3}{5} \right)^2}\]\[=2.\frac{3}{5}\sqrt{\frac{16}{25}}=\frac{6}{5}\frac{4}{5}=\frac{24}{25}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No probs. Become a fan ;)
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