the legs of an isosceles triangle are 13 units long and the altitude to the base is 12 units long. find the length of the base.

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the legs of an isosceles triangle are 13 units long and the altitude to the base is 12 units long. find the length of the base.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first draw it and you'll notice that the altitute bisects the triangle into 2 equal triangles so the bases will be equal, and so, use the pythagoreous theorem to find the base of one and the other one will be equal to it, then add, so you'll have this :\[c^2 = y^2 + x^2\] we're solving for x, so : \[x^2 = c^2 -y^2 = \sqrt{13^2 - 12^2}=\sqrt{25}= 5\] we have found the first base = 5, the other base is equal to it so : Base = B1 + B2 = 5 + 5 = 10 units ^_^
that makes more sence thanks
np :)

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