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anonymous
 5 years ago
how to find the focus and directrix for the parabola y=(x/4)^2 (squared)
anonymous
 5 years ago
how to find the focus and directrix for the parabola y=(x/4)^2 (squared)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Change it into standard form: \[x^2 = 4ay\] \[y = x^2/16 \] \[x^2=16y\] Find a: 4a=16 a=4 And then you find the vertex, which is (0,0) From there you can deduce that the focus will be (0,4) Directrix is y=4
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