anonymous
  • anonymous
ok, i need to simplyfy this and show all working: 3^3 / sqrt3^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[3^{3}\div \sqrt{3^{5}}\]
nowhereman
  • nowhereman
You should use \[\sqrt{x} = x^{\frac{1}{2}}\]
anonymous
  • anonymous
how

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nowhereman
  • nowhereman
use power rules, and \[\frac{x}{y} = x\cdot y^{-1}\]
nowhereman
  • nowhereman
You do have the same bases there, so all you need no know then is what \[x^a \cdot x^b\] is
anonymous
  • anonymous
oh, so it will be like \[3^{3-(1/5)}\] right?
nowhereman
  • nowhereman
nearly, but: \[\left( x^a \right) ^b = x^{a\cdot b} \]
anonymous
  • anonymous
\[\sqrt{3^{5}} = 3^{1/5} . so you get 3^{3}/ \]
anonymous
  • anonymous
you get 3^3 / 3^1/5
anonymous
  • anonymous
sqrt3
anonymous
  • anonymous
hence that will be \[3^{3-1/5}\]
nowhereman
  • nowhereman
that is exactly the mistake! \[ \sqrt{3^5} = \left( 3^5 \right)^{\frac{1}{2}}\]
anonymous
  • anonymous
oh no i think i get it wrong. that should be 3^5/2
anonymous
  • anonymous
hence, its \[3^{3-}\]
anonymous
  • anonymous
My answer is true SQRT(3)
anonymous
  • anonymous
its 3^3-5/2 = 3^1/2
nowhereman
  • nowhereman
And just for completeness, \[x^{\frac{1}{5}} = \sqrt[5]{x} \]
anonymous
  • anonymous
the answer is \[\sqrt{3}\] right?
anonymous
  • anonymous
duc, how do you get sqrt3?
anonymous
  • anonymous
I know the answere, but I dont know how to get to the answer
anonymous
  • anonymous
\[3^{3-5/2}\]
anonymous
  • anonymous
ok, guys, i appreciate you helping me, i just became your fan
anonymous
  • anonymous
First , You 3^5=3*3^4, so SQRT(3^5)=SQRT(3)*3^2,===>(3^3)/(SQRT(3)*3^2)=3/SQRT(3)=SQRT(3) It may be TRUE
anonymous
  • anonymous
ok, thankyou
anonymous
  • anonymous
No problem() good luck

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