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If your answer's E, when you sub. x=b in, you don't get zero. You should get zero because it's a root of the polynomial.
but isn't (x+2)^2 .. -2 to the left..?
b is in the positive side of the number line.
Two other things to consider - the shape of the graph is such that the coefficient of x^3 is negative, and there's a double root at a since it just touches the axis and there are no complex roots (if there were, it would look different).
Those three pieces of information should kill four of the five possibilities.
but b is (x-b)^2
shouldnt that be to the right
or do we count the negative outside the bracket as well?
The negative outside the bracket is allowing you to have a negative coefficient on x^3, which is what you need.
Do you want me to go through them?
Well, A is out because the coefficient of x^3 will be positive.
C, D, E are out because you have a double root at a, which means the factor containing a should be raised to the power of 2.
ohhh I get it now :) Thanks for your time :)