anonymous
  • anonymous
Is the answer E ? http://img17.imageshack.us/img17/8670/andysnap009.png
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
If your answer's E, when you sub. x=b in, you don't get zero. You should get zero because it's a root of the polynomial.
anonymous
  • anonymous
but isn't (x+2)^2 .. -2 to the left..?
anonymous
  • anonymous
b is in the positive side of the number line.

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More answers

anonymous
  • anonymous
Two other things to consider - the shape of the graph is such that the coefficient of x^3 is negative, and there's a double root at a since it just touches the axis and there are no complex roots (if there were, it would look different).
anonymous
  • anonymous
Those three pieces of information should kill four of the five possibilities.
anonymous
  • anonymous
but b is (x-b)^2
anonymous
  • anonymous
shouldnt that be to the right
anonymous
  • anonymous
sorry (x-a)^2
anonymous
  • anonymous
or do we count the negative outside the bracket as well?
anonymous
  • anonymous
The negative outside the bracket is allowing you to have a negative coefficient on x^3, which is what you need.
anonymous
  • anonymous
Do you want me to go through them?
anonymous
  • anonymous
yes please
anonymous
  • anonymous
Well, A is out because the coefficient of x^3 will be positive.
anonymous
  • anonymous
C, D, E are out because you have a double root at a, which means the factor containing a should be raised to the power of 2.
anonymous
  • anonymous
Leaves B
anonymous
  • anonymous
ohhh I get it now :) Thanks for your time :)
anonymous
  • anonymous
No probs.

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