anonymous
  • anonymous
Shortanswer question http://img151.imageshack.us/img151/6880/andysnap013.png
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Two lines will be parallel if they have the same gradient. Lines in the form\[y=mx+b\]are gradient-intercept form. If you rearrange your equations into that form, you can compare the gradients. To make the other line parallel, choose 'a' that will give you a gradient equal to the other.
anonymous
  • anonymous
how do we re arrange? so is 5 from (5x) the gradient for the first one and a from (ax) the gradient of the other?
anonymous
  • anonymous
\[5x-y+10=0 \rightarrow y=5x+10\]after adding 10 to both sides.

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anonymous
  • anonymous
The first line has gradient 5.
anonymous
  • anonymous
\[ax+4y-3=0 \rightarrow 4y=3-ax \rightarrow y = \frac{3-ax}{4}=-\frac{a}{4}x+\frac{3}{4}\]
anonymous
  • anonymous
You need a such that\[-\frac{a}{4}=5\]
anonymous
  • anonymous
So a is -20.
anonymous
  • anonymous
how did that become -a/4 x + 3/4 ?
anonymous
  • anonymous
\[y=\frac{3-ax}{4}=\frac{3}{4}-\frac{ax}{4}=-\frac{ax}{4}+\frac{3}{4}=-\frac{a}{4}x+\frac{3}{4}\]
anonymous
  • anonymous
oh okay makes sense :))) I'm just not so good at re arranging.
anonymous
  • anonymous
practice practice practice so you don't get ruined in tests for nothing
anonymous
  • anonymous
Very true :D

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