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anonymous

  • 5 years ago

Shortanswer question http://img151.imageshack.us/img151/6880/andysnap013.png

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  1. anonymous
    • 5 years ago
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    Two lines will be parallel if they have the same gradient. Lines in the form\[y=mx+b\]are gradient-intercept form. If you rearrange your equations into that form, you can compare the gradients. To make the other line parallel, choose 'a' that will give you a gradient equal to the other.

  2. anonymous
    • 5 years ago
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    how do we re arrange? so is 5 from (5x) the gradient for the first one and a from (ax) the gradient of the other?

  3. anonymous
    • 5 years ago
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    \[5x-y+10=0 \rightarrow y=5x+10\]after adding 10 to both sides.

  4. anonymous
    • 5 years ago
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    The first line has gradient 5.

  5. anonymous
    • 5 years ago
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    \[ax+4y-3=0 \rightarrow 4y=3-ax \rightarrow y = \frac{3-ax}{4}=-\frac{a}{4}x+\frac{3}{4}\]

  6. anonymous
    • 5 years ago
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    You need a such that\[-\frac{a}{4}=5\]

  7. anonymous
    • 5 years ago
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    So a is -20.

  8. anonymous
    • 5 years ago
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    how did that become -a/4 x + 3/4 ?

  9. anonymous
    • 5 years ago
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    \[y=\frac{3-ax}{4}=\frac{3}{4}-\frac{ax}{4}=-\frac{ax}{4}+\frac{3}{4}=-\frac{a}{4}x+\frac{3}{4}\]

  10. anonymous
    • 5 years ago
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    oh okay makes sense :))) I'm just not so good at re arranging.

  11. anonymous
    • 5 years ago
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    practice practice practice so you don't get ruined in tests for nothing

  12. anonymous
    • 5 years ago
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    Very true :D

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spraguer (Moderator)
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