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anonymous

  • 5 years ago

summation (3^n)( n!)/(n^n) does the above series converge or diverge when n goes to infinity?

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  1. anonymous
    • 5 years ago
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    Use Ratio test

  2. anonymous
    • 5 years ago
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    or Root test

  3. anonymous
    • 5 years ago
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    i know that but i m getting it to be convergent when it is a divergent series

  4. anonymous
    • 5 years ago
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    ya it is divergent the limit is 3e^(-1) which is larger than 1

  5. anonymous
    • 5 years ago
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    how did u get e?

  6. anonymous
    • 5 years ago
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    Ratio test lim |a_(n+1)/a_n| = lim 3[n/(n+1)]^n

  7. anonymous
    • 5 years ago
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    o yea... so n/n+1)^n = e right

  8. anonymous
    • 5 years ago
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    sorry 1/e

  9. anonymous
    • 5 years ago
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    yup, the limit is 1/e

  10. anonymous
    • 5 years ago
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    Do you know how to get that limit?

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spraguer (Moderator)
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