anonymous
  • anonymous
0=arcsin(-1/2) find cos(x), tan(x), cot(x), sec(x), csc(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
something is missing from the 0 = arcsin(-1/2)...because arcsin(-1/2) cant be 0
anonymous
  • anonymous
\[\sin^{-1}(-1/2) =0 \] or \[\sin^{-1} (x)=0\]???
anonymous
  • anonymous
because arcsine(-1/2) can't be zero as sklee said

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anonymous
  • anonymous
I meant arcsin(-1/2)=x :)
anonymous
  • anonymous
I wrote it wrong, the 0 is supposed to be an x. It was originally a theta, but the keyboard does not have the theta symbol so i replaced it with an x. x=arcsin(-1/2) find cos(x), tan(x), cot(x), sec(x), csc(x)
anonymous
  • anonymous
ok first you find the x which is clearly either in the 3rd or 4th quadrant because it's negative , that's: \[x=210^o, x=330^o\]
anonymous
  • anonymous
Now just substitute for each value of x in each function.
anonymous
  • anonymous
if you're wondering how I got the values of x, it's because sinx has a value of 1/2 when x=30, then I took the correspondent to 30 in both 3rd and 4th quadrant in order to get the negative value., to do that to get the value in the 3rd quadrant just add 180 to 30 to get 210. and to get the angle in the 4th quadrant just subtract 30 from 360 to get 330
anonymous
  • anonymous
jajuan, how old are you?
anonymous
  • anonymous
he looks like a baby in the picture:P.. just kidding
anonymous
  • anonymous
I understand all of the degrees and radians, but for some reason it didn't run through my head to apply 330 to the other functions lol and I am 20
anonymous
  • anonymous
well don't take 330.. take -30, they are the same
anonymous
  • anonymous
cool thanks
anonymous
  • anonymous
you're welcome.. I just hope the answer makes sense to you, if it does, you can fan me.. I don't mind at all ;)

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