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anonymous
 5 years ago
0=arcsin(1/2) find cos(x), tan(x), cot(x), sec(x), csc(x)
anonymous
 5 years ago
0=arcsin(1/2) find cos(x), tan(x), cot(x), sec(x), csc(x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0something is missing from the 0 = arcsin(1/2)...because arcsin(1/2) cant be 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sin^{1}(1/2) =0 \] or \[\sin^{1} (x)=0\]???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because arcsine(1/2) can't be zero as sklee said

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I meant arcsin(1/2)=x :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I wrote it wrong, the 0 is supposed to be an x. It was originally a theta, but the keyboard does not have the theta symbol so i replaced it with an x. x=arcsin(1/2) find cos(x), tan(x), cot(x), sec(x), csc(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok first you find the x which is clearly either in the 3rd or 4th quadrant because it's negative , that's: \[x=210^o, x=330^o\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now just substitute for each value of x in each function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you're wondering how I got the values of x, it's because sinx has a value of 1/2 when x=30, then I took the correspondent to 30 in both 3rd and 4th quadrant in order to get the negative value., to do that to get the value in the 3rd quadrant just add 180 to 30 to get 210. and to get the angle in the 4th quadrant just subtract 30 from 360 to get 330

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0jajuan, how old are you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he looks like a baby in the picture:P.. just kidding

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understand all of the degrees and radians, but for some reason it didn't run through my head to apply 330 to the other functions lol and I am 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well don't take 330.. take 30, they are the same

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're welcome.. I just hope the answer makes sense to you, if it does, you can fan me.. I don't mind at all ;)
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