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anonymous
 5 years ago
(4x^2y)^3
I really need help, I still don't understand.
anonymous
 5 years ago
(4x^2y)^3 I really need help, I still don't understand.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ (4x^{2y})^{3} is this what you mean?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(ab^{c})^{d} = a^{d} b ^{cd}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it will be \[4^{3}x ^{6y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0remember that y has an implicit exponent of 1, and 1*3 = 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i meant (4x to the second power than y)^3 the y is not part of the exponent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, so it's \[(4x ^{2}y)^{?}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the concept is the same, 4^3 x^6 y^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think the question is :\[(4x^2y)^3\] right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes thats right, i just dont understand how to solve it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As I said, when raising a product to a power, you multiply the exponents of the factors. So the 3 would be multiplied to the power of the 4 factor, and the power of the x factor, and the power of the y factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, first of all you've got to mulitply the power 3 with the given between the brackets and you'll get ^_^: \[=(4)^3 x^6 y^3 = 48x^6y^3\] is it clearer now ? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(4)^3 \ne 48 \] \[(4)^3 = 64 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol! sry >_< silly mistake , thank you polpak :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you understand it now courtney ^_^?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just substitute the power to each :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just pass the power out to each*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, kind of but there is another problem now that is in the same format but is a fraction and has that equal sign with a / through it. grr i hate math lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't say that, look at the problem , write it down on paper and try to use tha same concept like the one here :) The problem never gets harder, it just gets more detailed ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nothing changes, just apply the same rule :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The rule applies equally to division. The only part that gets messy is when you have a sum that you're raising to a power.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im trying to stay positive, thank you so much for your help you two are life savers! im writing all the work you just sent as my work shown but what part is the part that i put in the space for the answer to the problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try to see if you can figure it out from what we've said. We'll check your answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok im working it out now than ill post it on here, thank you again.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(((3p ^{3}v ^{4} \ s ^{4}))^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok this is a fraction the s^4 is on the bottom and it also says s with the equal sign / 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got 9p^6y^8 over s^8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So.. \[(3p^3v^4/s^4)^2, s \ne 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then yes, that is the correct answer. Good job!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yayyy thank you, even my professor cant teach me math and over the computer you got right into my head lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It may be somewhat helpful to expand the exponents for a while to see what is happening. \[(3p^3v^4/s^4)^2 = [(3pppvvvv)/(ssss)]^2 \] \[= [(3pppvvvv)(3pppvvvv)]/[(ssss)(ssss)]\] \[= [(3*3)ppppppvvvvvvvv]/[ssssssss]\] \[= 9p^6v^8/s^8\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that acutally helps alot, can i ask you on more question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so i know how to do this in a normal way but they want it in exponential form and im confused. the first is (5^3)^3 and the next is in fraction form which is even worse lol (r/s)^6 (s\[\neq\]0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So try to expand it out. \[(5^3)^3 = (5^3)(5^3)(5^3)\] Now how would you expand that further?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0five times five times five than add the exponents?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[5^3 = 5*5*5\] \[\rightarrow 5^3*5^3*5^3 = (5*5*5)*(5*5*5)*(5*5*5)\] \[=5^?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0awesome now to the fraction, can you help me with that one?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we can see that the faster way to arrive at the same result would be to simply : \[(5^3)^3 = 5^{3*3} = 5^9\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so you multiply the exponents too?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, remember when we expanded it out, we said that we had three groups with three 5's each. So how many 5's do we have multiplied together? 3*3 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, im trying to keep up im just so lost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you're not comfortable with multiplying the exponents, just try expanding the next one out for yourself. \[a^6 = a*a*a*a*a*a\] \[ \rightarrow (r/s)^6 =\ ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We'll just go one step at a time.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would i seperate them and do r*r*r*r*r*r and s*s*s*s*s*s?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, just multiply the whole thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so r/s*r/s*r/s*r/s*r/s*r/s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but keep the parens so it's more readable. \[(r/s)*(r/s)*(r/s)*(r/s)*(r/s)*(r/s)\] And when we multiply two fractions, we do what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0top times top bottom times bottom?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. And here again we can arrive at this answer in a more direct way once we understand the process \[ (r/s)^6 = (r^1/s^1)^6 = r^{1*6}/s^{1*6} = r^6/s^6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that would be the answer correct since we do not have the values for r and s? what about the =/ thing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0They have to make the restriction \[s \ne 0\] because if s is 0 then you're dividing by 0 which is not defined. That answer is correct regardless of what r and s is. If we know more about them we might be able to simplify further (if s was 2 and r was 4 for example). But even in that case our answer is correct. It just might not be in the form they're looking for.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yayyy you are so amazing and kind hearted. that you so so much!
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