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anonymous
 5 years ago
find the eqaution of the tangent plane at the point (2,2) on the surface z = sin (x^y)
anonymous
 5 years ago
find the eqaution of the tangent plane at the point (2,2) on the surface z = sin (x^y)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01)first find the derivative of the following equation = m =equation of the slope 2) substitute x to find the slope 3) substitute the rest of your given in the following equation to find the equation of the tangent line : yp  y = m(x  xp) and simply solve ^_^ clearer now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the question is not asking about the tangent line in 2D, but about the tangent plane on a surface

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it \[z=\sin (xy)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would this involve the del operator (sum of partial derivatives)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let \[f(x,y,z)=z\sin(xy)\] grad f(x,y,z) = \[<ycos(xy),xcos(xy),1>\] grad f(2,2,z)= <2cos(4),2cos(4),1>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the equation of the tangent plane will be: 2cos(4)(x2)2cos(4)(y2)+(zsin(4))=0 simplify!!
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