anonymous
  • anonymous
find the eqaution of the tangent plane at the point (2,2) on the surface z = sin (x^y)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1)first find the derivative of the following equation = m =equation of the slope 2) substitute x to find the slope 3) substitute the rest of your given in the following equation to find the equation of the tangent line : yp - y = m(x - xp) and simply solve ^_^ clearer now?
anonymous
  • anonymous
the question is not asking about the tangent line in 2D, but about the tangent plane on a surface
anonymous
  • anonymous
is it \[z=\sin (xy)\]

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anonymous
  • anonymous
lol sorry ^^"
anonymous
  • anonymous
Would this involve the del operator (sum of partial derivatives)?
anonymous
  • anonymous
let \[f(x,y,z)=z-\sin(xy)\] grad f(x,y,z) = \[<-ycos(xy),-xcos(xy),1>\] grad f(2,2,z)= <-2cos(4),-2cos(4),1>
anonymous
  • anonymous
the equation of the tangent plane will be: -2cos(4)(x-2)-2cos(4)(y-2)+(z-sin(4))=0 simplify!!
anonymous
  • anonymous
I gotta go now

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