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anonymous

  • 5 years ago

find the eqaution of the tangent plane at the point (2,2) on the surface z = sin (x^y)

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  1. anonymous
    • 5 years ago
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    1)first find the derivative of the following equation = m =equation of the slope 2) substitute x to find the slope 3) substitute the rest of your given in the following equation to find the equation of the tangent line : yp - y = m(x - xp) and simply solve ^_^ clearer now?

  2. anonymous
    • 5 years ago
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    the question is not asking about the tangent line in 2D, but about the tangent plane on a surface

  3. anonymous
    • 5 years ago
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    is it \[z=\sin (xy)\]

  4. anonymous
    • 5 years ago
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    lol sorry ^^"

  5. anonymous
    • 5 years ago
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    Would this involve the del operator (sum of partial derivatives)?

  6. anonymous
    • 5 years ago
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    let \[f(x,y,z)=z-\sin(xy)\] grad f(x,y,z) = \[<-ycos(xy),-xcos(xy),1>\] grad f(2,2,z)= <-2cos(4),-2cos(4),1>

  7. anonymous
    • 5 years ago
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    the equation of the tangent plane will be: -2cos(4)(x-2)-2cos(4)(y-2)+(z-sin(4))=0 simplify!!

  8. anonymous
    • 5 years ago
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    I gotta go now

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