## anonymous 5 years ago find the eqaution of the tangent plane at the point (2,2) on the surface z = sin (x^y)

1. anonymous

1)first find the derivative of the following equation = m =equation of the slope 2) substitute x to find the slope 3) substitute the rest of your given in the following equation to find the equation of the tangent line : yp - y = m(x - xp) and simply solve ^_^ clearer now?

2. anonymous

the question is not asking about the tangent line in 2D, but about the tangent plane on a surface

3. anonymous

is it $z=\sin (xy)$

4. anonymous

lol sorry ^^"

5. anonymous

Would this involve the del operator (sum of partial derivatives)?

6. anonymous

let $f(x,y,z)=z-\sin(xy)$ grad f(x,y,z) = $<-ycos(xy),-xcos(xy),1>$ grad f(2,2,z)= <-2cos(4),-2cos(4),1>

7. anonymous

the equation of the tangent plane will be: -2cos(4)(x-2)-2cos(4)(y-2)+(z-sin(4))=0 simplify!!

8. anonymous

I gotta go now