Solve for W: 2w^3-w^2+6w-3=0

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Solve for W: 2w^3-w^2+6w-3=0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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factor by grouping and you'll get ^_^:\[= w^2(2w-1) + 3(2w-1) = (2w-1)(w^2+3)\]
Thanks!
np ^_^

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Other answers:

you can also use horner's method of factoring polynomial
not to be a stickler in the mud; but there is no "W" in the problem :)
lol, he meant w :)
meant, schmeant.... lol
lol, alright ^_^
Not to be a stickler, but the phrase is, "a stick in the mud"
\[\log_{17} 17^{y}\]
Remember that \[k = log_{b}x \iff b^k = x\]
so let \[ k = log_{17} 17^y \rightarrow 17^? = 17^y\]
canadian eh....
\[\log_{17} 17^{y}\]
... are you repeating the question for any particular reason?
Nah, i got it. typo. Thanks anyway

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