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anonymous
 5 years ago
Intergration please solve intergral tanx^3 dx
anonymous
 5 years ago
Intergration please solve intergral tanx^3 dx

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0odd degree trig functions; I think its easier to split them up into groups of something...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Rewrite it as ∫tan^2(x)*tan(x) dx > ∫(sec^2(x)1)*tan(x) dx = ∫sec^2(x)tan(x)  tan(x) dx. Let u=tan(x).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, it is quite simple actually, just wait a minute and sstarica will show you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rewrite it and you'll get :\[\int\limits_{}^{}sinx^3/cosx^3 dx\] use u substitution for cosx^3 ^_^ give it a try :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, and ssarica, gratz on making a Superstar, I guess I cant call you starlet anymore

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, call me whatever you want and thank you ^_^, some of the fanning came from you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yup, whole 4 fannings

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre! are you encouraging students on using calculators instead of thinking about it?!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at 101 fans you get to be a "hero"....its a shame really, all that work just to become a sandwich....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0different times, different accounts, but same me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) I don't really care much about the fanning process

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the mr proffesor is more of an "exercise" in math than it is a calculator :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, anyway did you understand it deidre? ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@sstarica: I'm not sure if your method works, it ends up giving you 1/3 * ∫1/cos^5(x) dx. :/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02x6=? 12 (green light)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for reals? let me try

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, sorry. Thought you typed something else ;P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, you're right it doesn't work ^^" sorry for the mess again diedre, ignore my answer. Thank you Quantum ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0deidre is away, geting some hotdogs for me and me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now let me check if my answer works...xD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so dont worry, you have some time to clear the mess before he comes back

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[du = 3x^2sinx^3dx\] which is wrong. you can't substitute it there, my dearest apologies ^^"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah, let me expand my answer to make it clearer: ∫tan(x)sec^2(x) dx  ∫tan(x) dx. In the first integral, let u=tan(x), and in the second it integrates cleanly. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why did you put tanxsec^2x? where did you get it from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^3 acts as an angle here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and not the power of tan :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, guys, I am about to go to sleep, just going to workout abit and maybe eat something and i am off.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, nice, so we are going to beds together again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0anyway, solve the question and I'm off to bed, sorry ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going to bed ALONE >_>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I sayed BEDS with an S, not BED :D LOL, I knew it you have interesting thoughts in your head :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got it from the relation tan^2(x) = sec^2(x)  1. ∫tan^3(x)dx = ∫tan^2(x)*tan(x) dx = ∫(sec^2(x)1)*tan(x) dx = ∫tan(x)sec^2(x)  tan(x) dx = ∫tan(x)sec^2(x) dx  ∫tan(x) dx. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I never think of such things angoo =P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes but quantum the question is :\[\int\limits_{}^{}tanx^3\] and not : \[\int\limits_{}^{}\tan^3x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm... well, I don't too, becouse things like those should be practice once married

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0quantum you copied the question wrong lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good, smart girl, not the "new era" type

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah, I'm old fashioned ^_^ more classy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wonderful, smart, classy, what else could one want....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Erm...alright, then we'll see when deidre clears it up. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like in, what else would I look for in a friend

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol , I agree Quantum

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aww, angoo, you're soo sweet ^_^

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im sticking with my safety net....(S) x^2 dx..... :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not sweet, just relaxed and not trying to be someone I am not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol amistre! and yes you are sweet andy ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, thanks, going to the dream world now, I think I will dream about beautiful land with happy little rabbits and dears and bears living together, and I will be ther too, we will play and have fun....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lala land, lol, I'm off to bed too, good night ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you are welcome :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) I was about to say "don't let the bugs bite" but it is getting old, so..
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