anonymous
  • anonymous
Intergration please solve intergral tanx^3 dx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
odd degree trig functions; I think its easier to split them up into groups of something...
anonymous
  • anonymous
Re-write it as ∫tan^2(x)*tan(x) dx ---> ∫(sec^2(x)-1)*tan(x) dx = ∫sec^2(x)tan(x) - tan(x) dx. Let u=tan(x).
anonymous
  • anonymous
well, it is quite simple actually, just wait a minute and sstarica will show you

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anonymous
  • anonymous
re-write it and you'll get :\[\int\limits_{}^{}sinx^3/cosx^3 dx\] use u substitution for cosx^3 ^_^ give it a try :)
anonymous
  • anonymous
LOL andy :D
amistre64
  • amistre64
Here, use this :)
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anonymous
  • anonymous
oh, and ssarica, gratz on making a Superstar, I guess I cant call you starlet anymore
anonymous
  • anonymous
lol, call me whatever you want and thank you ^_^, some of the fanning came from you :)
anonymous
  • anonymous
yup, whole 4 fannings
anonymous
  • anonymous
amistre! are you encouraging students on using calculators instead of thinking about it?!
amistre64
  • amistre64
at 101 fans you get to be a "hero"....its a shame really, all that work just to become a sandwich....
anonymous
  • anonymous
different times, different accounts, but same me
anonymous
  • anonymous
:) I don't really care much about the fanning process
amistre64
  • amistre64
the mr proffesor is more of an "exercise" in math than it is a calculator :)
anonymous
  • anonymous
lol, anyway did you understand it deidre? ^_^
anonymous
  • anonymous
@sstarica: I'm not sure if your method works, it ends up giving you -1/3 * ∫1/cos^5(x) dx. :/
amistre64
  • amistre64
2x6=? 12 (green light)
anonymous
  • anonymous
for reals? let me try
anonymous
  • anonymous
Whoops, not quite..
anonymous
  • anonymous
no lol , it works!
anonymous
  • anonymous
Oh, sorry. Thought you typed something else ;P
anonymous
  • anonymous
wait, you're right it doesn't work ^^" sorry for the mess again diedre, ignore my answer. Thank you Quantum ^_^
anonymous
  • anonymous
deidre is away, geting some hotdogs for me and me
anonymous
  • anonymous
Now let me check if my answer works...xD
anonymous
  • anonymous
so dont worry, you have some time to clear the mess before he comes back
anonymous
  • anonymous
\[du = -3x^2sinx^3dx\] which is wrong. you can't substitute it there, my dearest apologies ^^"
anonymous
  • anonymous
Ah, let me expand my answer to make it clearer: ∫tan(x)sec^2(x) dx - ∫tan(x) dx. In the first integral, let u=tan(x), and in the second it integrates cleanly. :P
anonymous
  • anonymous
why did you put tanxsec^2x? where did you get it from
anonymous
  • anonymous
x^3 acts as an angle here
anonymous
  • anonymous
and not the power of tan :)
anonymous
  • anonymous
ok, guys, I am about to go to sleep, just going to workout abit and maybe eat something and i am off.
anonymous
  • anonymous
same, I'm tired
anonymous
  • anonymous
oh, nice, so we are going to beds together again
anonymous
  • anonymous
anyway, solve the question and I'm off to bed, sorry ^_^
anonymous
  • anonymous
I'm going to bed ALONE >_>
anonymous
  • anonymous
I sayed BEDS with an S, not BED :D LOL, I knew it you have interesting thoughts in your head :)
anonymous
  • anonymous
I got it from the relation tan^2(x) = sec^2(x) - 1. ∫tan^3(x)dx = ∫tan^2(x)*tan(x) dx = ∫(sec^2(x)-1)*tan(x) dx = ∫tan(x)sec^2(x) - tan(x) dx = ∫tan(x)sec^2(x) dx - ∫tan(x) dx. :P
anonymous
  • anonymous
nope :)
anonymous
  • anonymous
I never think of such things angoo =P
anonymous
  • anonymous
yes but quantum the question is :\[\int\limits_{}^{}tanx^3\] and not : \[\int\limits_{}^{}\tan^3x\]
anonymous
  • anonymous
hmm... well, I don't too, becouse things like those should be practice once married
anonymous
  • anonymous
I agree :)
anonymous
  • anonymous
quantum you copied the question wrong lol
anonymous
  • anonymous
good, smart girl, not the "new era" type
anonymous
  • anonymous
nah, I'm old fashioned ^_^ more classy
anonymous
  • anonymous
wonderful, smart, classy, what else could one want....
anonymous
  • anonymous
want what? ._.
anonymous
  • anonymous
Erm...alright, then we'll see when deidre clears it up. :P
anonymous
  • anonymous
like in, what else would I look for in a friend
anonymous
  • anonymous
lol , I agree Quantum
anonymous
  • anonymous
aww, angoo, you're soo sweet ^_^
amistre64
  • amistre64
im sticking with my safety net....(S) x^2 dx..... :)
anonymous
  • anonymous
not sweet, just relaxed and not trying to be someone I am not
anonymous
  • anonymous
lol amistre! and yes you are sweet andy ^_^
anonymous
  • anonymous
well, thanks, going to the dream world now, I think I will dream about beautiful land with happy little rabbits and dears and bears living together, and I will be ther too, we will play and have fun....
anonymous
  • anonymous
lala land, lol, I'm off to bed too, good night ^_^
anonymous
  • anonymous
and you are welcome :)
anonymous
  • anonymous
night night :)
anonymous
  • anonymous
sleep tight ~
anonymous
  • anonymous
:) I was about to say "don't let the bugs bite" but it is getting old, so..
anonymous
  • anonymous
lol, bye
anonymous
  • anonymous
bye

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