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anonymous
 5 years ago
use the subtitution method to solve.
x^2 + 2y = 9
x  y + 3 = 0
can someone help me?
anonymous
 5 years ago
use the subtitution method to solve. x^2 + 2y = 9 x  y + 3 = 0 can someone help me?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from equation (2): y=x+3 > (3) substitute for y with x+3, you get: \[x^2+2(x+3)=9 \implies x^2+2x3=0\] factorize it to get: \[(x+3)(x1)=0 \implies x=3, x=1\] substitute for each value of x in equation 3\[x=3 \implies y=3+3=0\] \[x=1 \implies y=1+3=4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0therefore the problem has two solutions: \[(x,y)=(3,0) , (x,y)=(1,4)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I get it. My answer was really close to that. Thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're welcome :).. feel free to fan me ;)
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