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1-5i + n = 0
1+5i +m = 0
n= -1+5i
m= -1-5i
(1-5i -1+5i) (1+5i -1-5i)

1 +5i -1 -5i
-5i -25i^2 +5i +25i^2
-1 -5i +1 +5i
5i +25i^2 -5i -25i^2

guess it aint gonna work out like i thought :) gotta head to marketing class now; Ciao :)

? Ok.

Well wait. Which part don't you understand?

Do you agree that
\[ (x-a)(x-b) = x^2 - ax -bx +ab \]

Yes I agree. That would be just simply distrubtng....

Did I lose you?

Kinda.. because I dont know where the zero comes from??

\[ If\ x = a, then\ (x-a) = (a-a) = 0 \rightarrow (x-a)(x-b) = 0*(a-b) = 0\]

Thanks for your help.. I dont want to waste anymore of your time...

... You're not wasting my time. Did you understand my last sentence?

\[ \rightarrow \] just means 'therefore'

I wish I did...

Let x = a. Then (x-a) = (a-a). (a-a) = ?

0?

Yes. a - a = 0. No matter what 'a' is.

Ok.. so now that I know that.. what signifigance does that have in my problem?

Does that make sense?