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anonymous
 5 years ago
any help would be appreciated.. I have a test, and I am unsure of my probs below... ty.
anonymous
 5 years ago
any help would be appreciated.. I have a test, and I am unsure of my probs below... ty.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where are the problems?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have one... Given that the polynomial f(x) has a zero at x=2 find the remaining zeros.. f(x)=x^310x^2+41x50

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0You can factor (x2) from f(x) if it has a zero at x=2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What does that mean? It says my answer should be in a+bi form?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0having a zero at x=2 means that (x2) is one factor of f(x), you have to find the other factors.. using long division gives: \[f(x)=(x2)(x^28x+25)=0\] you already have the solution x=2 to find the other solutions solve the quadratic equation: \[x^28x+25=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0using the quadratic formula gives us the two remaining solutions: \[x=43i, x=4+3i\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to use the quadratic formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Long division.. we are being taught syntheic.. is that ok?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0there is only one solution to that division, and that step is really trivial it does not matter how you solve it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you show me the way the quadratic formula is worked out on here??

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0The solution formula for \[ x^2 + px + q = 0\] is \[x = \frac{p}{2} \pm \sqrt{\frac{p^2}{4}  q}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And thats the quadratic formula??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0becasue I have never seen that before??

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Some schools teach the form \[ax^2 + bx +c = 0\] where you would of course get a formula which is a bit different. But the above is the exact solution formula for such quadratic problems.
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